π Pro Players - Welcome to the Community!
Comments
-
Sorry as you haven't becoming Pro Player yet! @Kerrie and @Peanut7139 π
Then Attention! YouΒ have connected/ticked link your King and Community accounts already, that's right! That optionΒ will be gone/dissappearedΒ after youΒ have connected/tickedΒ it.
And whoΒ haven't connected/tickedΒ link your King and Community accounts and/orΒ commented itΒ yet, you can check my tipsΒ hereΒ how to connect/tick link your King and Community account on King Community first (if youΒ haven't connected/tickedΒ it yet). After youΒ connect/tick link your King and Community accountsΒ completed, youΒ may become Pro Player then you can comment it here that you will get Pro Player Badge on your view profile on King Community! ππ
And asΒ Lola PopΒ the Community Manager suggested another notes :
It's an automatic step, the system picks up the players who fit into the category, there's nothing they can check for you.
Please remember:Β Pro PlayersΒ play more, they are onΒ higher levelsΒ and/or they have been around for theΒ longest time!Β π€
Good luck! ππ
-
Hello everyone - it is great to see everyone is so excited about the new title of pro player. You will know if you are a pro player or not because it will show up in your profile and as a title on your posts. The recognition as a pro player is not done by the Community Mangers, but by the studio. You are not nominated for the title, it is calculated based upon several factors including how long you have played, the level you are at, how much you play the game(s) etc.
Don't despair if you aren't selected as a Pro Player yet, it is new to the community and you may see the title added to your profile sometime in the future.
Good Luck everyone and Happy Crushing! ππ¨π
-
-
@bearwithme it is my understanding that a player will never be a "Pro Player" if they do not link their accounts?
Is this correct?
What about all the players in the world? Our "Community" here only represents a small number of the big picture?
Maybe the CommunityTeam can provide some insight here? Would be helpful.
Κ β’α΄₯β’Κ