Can you solve Math Challenge Puzzle Games? ❓🔢

1. 3N (N+N+N) = 39, then N = 39/3 = 13.

Skip to 3. P + (N=13) + P = 23

Then 2P = 23 - (N=13) = 10

Finally P = 10/2 = 5

Can Solve 2. Followed same by 3.

So C = 25 - (P=5) = 20, then 20/2 = 10

So let's solve final answer :

(N=13) + (C=10) + (P=5) = 28 😉

1. 3R (R+R+R) = 60, then R = 60/3 = 20.

2. (R=20) + B + B = 30

Then 2B = 30 - 20 = 10

And finally B = 10/2 = 5

3. (B=5) -2Y = 3

-2Y = 3 (-5) = -2

* Y (each) = -2/-2 = 1 (positive number) *

So let's solve final answer :

B has 4 petals now, so 5/5 = 1 (each petals of B) and then 1X4 = 4 (4 petals of B)

Then make sure multiply first then can plus, that's answer! 😉

And finally, (Y=1) + (R=20) X (B=4 (4 Petals)) = 81 ➡️ (1 + 80)

1. 3R (R+R+R) = 24, then R = 24/3 = 8.

2. R has 6 petals now, so 8/8 = 1 (each petals of R) and then 1X6 = 6 (6 petals of R)

Then (T+B) + (T+B) + (R=6 (6 Petals)) = 26

After that, 2(T+B) = 26 - 6 = 20

And finally (T+B) = 20/2 =10

3. B + (T+B=10) + (R= 8(8 Petals)) = 21

Then B = 21-10-8 = 3

* T + (B=3) = 10, then T = 10 - 3 = 7 *

So let's solve final answer :

R has back to 6 petals again, so 6 (Petals).

Then make sure plus all of items in one group that's means use blanket in one group first then multiply and finally can plus, that's answer! 😉

And finally, (B+B=(3+3)) + (R(6 Petals)+T+B=(6+7+3)) X (T=7) = ?

(2B=6) + (R(6Petals)+T+B=16) X (T=7) = 118 ➡️ (6+112)

1a. +(+A) = +A

1b. +(-A) = -A

1c. -(+A) = -A

1d. -(-A) = +A

2. The BODMAS rule states we should calculate the Brackets first (2 + 4 = 6), then the Orders (5*2 = 25), then any Division or Multiplication (3 x 6 (the answer to the brackets) = 18), and finally any Addition or Subtraction (18 + 25 = 43). (You can search "What is BODMAS" on Google Search 😉)

3a. A + B = 10, then A = 10 - B

3b. A - B = 10, then A = 10 + B

3c. A X B = 10, then A = 10 / B

3d. A / B = 10, then A = 10 X B

4a. -2A = 10, then A = 10/-2 = -5

4b. -2A = -10, then A = -10/-2 = +5

(Followed same by 1.)

5a. A + A = 2A

5b. A - A = 0 and 3A - A = 2A

5c. A X A = A*2

5d. A / A = 1 and A*3 / A = A*2