my idea is related to all stars or contests or tournaments like winter games. Based on the number of “x” colour candies. If we complete the level with original moves left (not from running out of moves and buying more) can the “x” amount of moves left either multiply by “X” amount of moves left by the “X” colour candies collected, eg. 400 coloured candies collected and 10 moves left = 400 x 10. Or 400 candies collected, finished level with 2 original moves left =400x2=800 candies collected.
Or each move remaining add 100 “x” coloured candies for example. (This would be without the multiplication power, that would be additional if activating multiplyer by 10x for 30 mins) eg. 400 candies collected and 10 original moves left so 10 moves times 100 (10x100=1000) so 1000+400=1,400 (the activated multiplier would be additional the final number)
I think the moves remaining from original moves given per level, not added moves after running out, should count towards more coloured candies to win the leaderboard. It’s tougher to complete a level with moves left than to use every move to collect “x” coloured candies
Hope my suggestion helps.
Also, I haven’t been able to tell if coloured candies are collected from winning the level and having moves left, it’s been seeming like on winter games recently they’re not collected so winning the level early with “x” remaining moves left don’t count toward any collected coloured candies.
hope my suggestion makes sense! Really enjoy playing candy crush. Thanks :)