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# The chance to win Gold bars by combining blocker codes1️⃣2️⃣3️⃣ (finished)

Posts: 24,932 Candy Moderator
edited June 2022 in Contests

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Hi everyone 😍

I've come back to you with another fun contest and this time you have questions about the Candy Crush Saga Blocker's layer. Candy Crush Saga game has different layers of different blockers and you have to say the total sum according to the layer of blockers.

As an example I have given the picture of an icing blocker below👇

In the picture above there are 5 layers of icing so the code of blocker is 5 😊Now you will find the contest question in the picture below.🤩

There are a total of 6 blockers in the picture above and let me know by assembling the code of the layers.☝

✌✌ Rules

Give the answer using the Spoiler option and you will find the guide in the screenshot below 👇

It is mandatory🥍

🏆🏆 Rewards

At the end of the Competition, we will randomly select 5 (Five) winners from the correct answers and they will each get 20 Gold bars in their Candy Crush Saga game.

🗓 Dates: you will be able to participate in the Competition until 27th May, 2022.

Good luck everyone and happy crushing! 🍬 🍬

Terms and Conditions here.

## Comments

• Posts: 24,932 Candy Moderator
• Posts: 11,757 Soda Moderator

Hello!🙂

Probably:

15

• Posts: 7 Level 2

The first blocker is probably 3

second should be 3

third 1

fourth 4

fifth 2

sixth 2

So in total =15

• Posts: 4,144 Level 5

Hi

Toffee Swirl 3

Dark Chocolate 3

Bubblegum Pop 1

Rainbow Twist 4

Sugar Coat 2

Candy Cane Curl 2

Total 15

• Posts: 19,791 Level 5

Hi @Sukanta_Biswas my answer:

Toffee Swirl 3

Dark Chocolate 3

Bubblegum Pop 1

Rainbow Twist 4

Sugar Coat 2

Candy Cane Curl 2

3+3+1+4+2+2= 15

• Posts: 881 Level 4

3+3+1+4+2+2 = 15

Total: 15

• Posts: 669 Level 3

Hi,@Sukanta_Biswas my answer,

@Diamond_Lim thank you for the tag

15

• Posts: 270 Level 3

The first blocker is 3

Second 3

Third 1

Fourth 4

Fifth 2

Sixth 2

Total =15

• Posts: 1,519 Level 4

It's. 3+3+1+4+2+2=15

MY answer...thanks for tagging me

This discussion has been closed.